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  1. Question #bfcbb - Socratic

    May 19, 2017 · Copper has a molar mass of 63.546 g mol−1, which means that 1 mole of copper has a mass of 63.546 g. Now, in order to have 1 mole of copper, you need to have 6.022 ⋅ …

  2. Question #7908b - Socratic

    65.0 "g N"_2 Any time you want to convert between moles and grams of a substance, you must know that substance's molar mass, which is the mass of one mole of that substance. (One …

  3. Question #928a6 - Socratic

    (a) Use the molar mass to convert the mass of NaN3 to moles of NaN3. (b) Use the molar ratio (from the balanced equation) to convert moles of NaN3 to moles of N2.

  4. Question #b7de9 - Socratic

    To find the number of moles, we need the mass and the molar mass. The molar mass is given by the sum of the individual molar masses of the constituent atoms in the molecule.

  5. Question #e15e7 - Socratic

    You must use "69.68 g of Na"_2"S" to produce "50.00 g of TiS"_2. > There are four steps to answering this type of stoichiometry problem. Write the balanced equation for the reaction. …

  6. Question #9937f - Socratic

    We know the mass of #Fe# produced, which is given to be #700.0 * 10^6g# (I've converted it to grams because it will be easier to work with), and #Fe# 's molar mass - #55.8g/ (mol)# - which …

  7. 8 grams of barium carbonate (BaCO3) is needed to kill a rat

    Feb 21, 2018 · We first need to convert the amount of barium carbonate into moles. Barium carbonate BaCO3 has a molar mass of 197.34 g/mol. Here, there are 8 grams of barium …

  8. 3.01e22 Ag+ ions is present in? options a) 85 grams of AgNO3

    Explanation: #1# mole #= 6.023 xx 10^23# ions #Ag^+ =# #3.01 xx 10^22# ions No. of moles of #Ag^+ = # (#3.01# x #10^22# ions)/ (# 6.023 xx 10^23# ions) #=# # 0.0499# moles Molar …

  9. Question #58872 - Socratic

    18.5gal ⋅ 3.79L 1gal ⋅ 1000mL 1L ⋅ 0.703 g 1mL = 4.93 ⋅ 104g Use octane's molar mass to convert this mass to moles 4.93 ⋅ 104g ⋅ 1 mole octane 114.23g = 431.6 moles octane According to …

  10. Question #ddaf8 - Socratic

    We can rearrange this formula given the no of moles and the molar mass: