The question is why &arr and arr evaluates to the same number. If arr is a literal (not stored anyware), then the compiler should complain and say that arr is not an lvalue.

Mar 30, 2020 · 1 Suppose I have an array of integers called arr. I am trying to understand the distinction between *&arr and *&arr[0]. I read that in C++, arr is essentially a pointer to the first element in the …

Jan 13, 2021 · In fact it is just interpreting that it needs to go till the boundary as arr [::1] gives normal array. Is this just coded as a special case or is there something more going on?

Jul 10, 2016 · 7 what does *arr[] mean? As standalone expression *arr[] is not valid. For variable definitions there are two meanings here, depending of the context in which such an expression …

The trick is to use the expression (&arr) [1] - arr to get the array arr size. Both arr and &arr points to the same memory location, but they both have different types.

Oct 25, 2018 · def bubble_sort(arr): This is is a function definition. A function definition is preceded by the keyword def. Following that is the function's name. In this case it is called bubble_sort. What we …

Mar 1, 2016 · Your question involves a mix of basic Python syntax, and numpy specific details. In many ways it is the same for lists, but not exactly. arr[:, 0] returns the 1st column of arr (a view), arr[:,0]=10 …

Sep 29, 2011 · 3 41 4 5 In this example i = 3, so arr[3] = 40. It then increases the value from 40 to 41 .So arr[i]++ increments the value of this particular index and a[i++] first increments the index and …

Dec 27, 2019 · what is the working of arr [arr1,arr2] in numpy Asked 5 years, 11 months ago Modified 5 years, 11 months ago Viewed 1k times

May 12, 2021 · As others have mentioned, *(&arr + 1) triggers undefined behavior because &arr + 1 is a pointer to one-past-the end of an array of type int [7] and that pointer is subsequently dereferenced.